刘嘉柚 • 5个月前
#include <iostream> using namespace std; int main() { int a,b,g; double s; cin>>a>>b; s=a+(double)b/10; g=s/2.1; cout<<g; return 0; }
评论:
这才精简
#include<cstdio> int main(){ int a,b; scanf("%d%d",&a,&b); printf("%d",(a*10+b)/21); return 0; }
黄某写对了,这个的确更加精简