10316 - 邮票

已知一个 N 枚邮票的面值集合(如,{1 分,3 分})和一个上限 K —— 表示信封上能够贴 K 张邮票。计算从 1 到 M 的最大连续可贴出的邮资。

例如,假设有 1 分和 3 分的邮票;你最多可以贴 5 张邮票。很容易贴出 1 到 5 分的邮资(用 1 分邮票贴就行了),接下来的邮资也不难:

6 = 3 + 3 7 = 3 + 3 + 1 8 = 3 + 3 + 1 + 1 9 = 3 + 3 + 3 10 = 3 + 3 + 3 + 1 11 = 3 + 3 + 3 + 1 + 1 12 = 3 + 3 + 3 + 3 13 = 3 + 3 + 3 + 3 + 1。 然而,使用 5 枚 1 分或者 3 分的邮票根本不可能贴出 14 分的邮资。因此,对于这两种邮票的集合和上限 K=5,答案是 M=13。

输入

第 1 行: 两个整数,K 和 N。K(1 <= K <= 200)是可用的邮票总数。N(1 <= N <= 50)是邮票面值的数量。 第 2 行 .. 文件末: N 个整数,每行 15 个,列出所有的 N 个邮票的面值,面值不超过 10000。

输出

第 1 行: 一个整数,从 1 分开始连续的可用集合中不多于 K 张邮票贴出的邮资数。

样例

输入

5 2
1 3

输出

13

提示

Stamps

Given a set of N stamp values (e.g., {1 cent, 3 cents}) and an upper limit K to the number of stamps that can fit on an envelope, calculate the largest unbroken list of postages from 1 cent to M cents that can be created.

For example, consider stamps whose values are limited to 1 cent and 3 cents; you can use at most 5 stamps. It's easy to see how to assemble postage of 1 through 5 cents (just use that many 1 cent stamps), and successive values aren't much harder:

6 = 3 + 3 7 = 3 + 3 + 1 8 = 3 + 3 + 1 + 1 9 = 3 + 3 + 3 10 = 3 + 3 + 3 + 1 11 = 3 + 3 + 3 + 1 + 1 12 = 3 + 3 + 3 + 3 13 = 3 + 3 + 3 + 3 + 1. However, there is no way to make 14 cents of postage with 5 or fewer stamps of value 1 and 3 cents. Thus, for this set of two stamp values and a limit of K=5, the answer is M=13.

The most difficult test case for this problem has a time limit of 4 seconds.

PROGRAM NAME: stamps INPUT FORMAT Line 1: Two integers K and N. K (1 <= K <= 200) is the total number of stamps that can be used. N (1 <= N <= 50) is the number of stamp values.
Lines 2..end: N integers, 15 per line, listing all of the N stamp values, each of which will be at most 10000.

SAMPLE INPUT (file stamps.in) 5 2 1 3

OUTPUT FORMAT Line 1: One integer, the number of contiguous postage values starting at 1 cent that can be formed using no more than K stamps from the set.

SAMPLE OUTPUT (file stamps.out) 13

时间限制 1 秒
内存限制 128 MB
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