| Run ID | Author | Problem | Lang | Verdict | Score | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|---|
| 111856 | 李树强 | 不同路径 | C++ | Wrong Answer | 66 | 0 MS | 260 KB | 369 | 2023-11-25 08:31:27 |
#include<iostream> using namespace std; typedef long long ll; ll n, m, f[110][110]; bool a[110][110]; int main(){ cin >> n >> m; for(int i = 1; i <= n; i++) for(int j = 1; j <= m; j++) cin >> a[i][j]; for(int i = 1; i <= n; i++) for(int j = 1; j <= m; j++) if(!a[i][j]){ f[i][j] = min(f[i][j-1], f[i-1][j]) + 1; } cout << f[n][n]; return 0; }