Run ID | 作者 | 问题 | 语言 | 测评结果 | 分数 | 时间 | 内存 | 代码长度 | 提交时间 |
---|---|---|---|---|---|---|---|---|---|
139289 | 吴晨曦 | 买卖股票的最佳时机 | C++ | 解答错误 | 33 | 0 MS | 256 KB | 432 | 2024-03-23 00:13:52 |
#include <bits/stdc++.h> using namespace std; const int N = 1e6 + 005; int a[N], d[N]; int main() { int n, maxn = 0; cin >> n; for (int i = 1; i <= n; i++) cin >> a[i]; for (int i = 1; i <= n; i++) { int minn = -1e9; for (int j = i; j <= n; j++) minn = max(minn, a[i]); if (minn = a[i]) maxn = max(maxn, a[i]); else maxn = max(maxn, minn - a[i]); } cout << maxn << endl; return 0; }