提交时间:2024-01-25 11:09:42
运行 ID: 127951
#include<bits/stdc++.h> using namespace std; int n,k; double a[100005],l,r,mid,ans; int main(){ cin>>n>>k; for(int i=1;i<=n;i++){ cin>>a[i]; r=max(r,a[i]); } mid=r/2; while(r-l>=0.01){ //cout<<l<<" "<<r<<" "<<mid<<endl; int sum=0; for(int i=1;i<=n;i++){ sum+=floor(a[i]/mid); } if(sum>=k){ ans=l; l=mid+0.01; } else r=mid-0.01; mid=(l+r)/2; } printf("%.2f",ans); return 0; }